\Header{se.contrast}{Standard Errors for Contrasts in Model Terms}
\methalias{se.contrast.aov}{se.contrast}
\methalias{se.contrast.aovlist}{se.contrast}
\keyword{models}{se.contrast}
\begin{Description}\relax
Returns the standard errors for one or more contrasts in an \code{aov}
object.\end{Description}
\begin{Usage}
\begin{verbatim}
se.contrast(object, ...)
se.contrast.aov(x, contrast.obj,
  coef = contr.helmert(ncol(contrast))[, 1], data = NULL) 
se.contrast.aovlist(...)
\end{verbatim}
\end{Usage}
\begin{Arguments}
\begin{ldescription}
\item[\code{object}] A suitable fit, usually from \code{aov}.
\item[\code{contrast.obj}] The contrasts for which standard errors are
requested. This can be specified via a list or via a matrix. A single
contrast can be specified by a list of logical vectors giving the
cells to be contrasted. Multiple contrasts should be specified by a
matrix as returned by \code{contrasts}.
\item[\code{coef}] Used when \code{\{contrast.obj\}} is a list; it should be a
vector of the same length as the list with zero sum. The default
value is the first Helmert contrast, which contrasts the first and
second cell means specified by the list.
\item[\code{data}] The data frame used to evaluate \code{contrast.obj}.
\end{ldescription}
\end{Arguments}
\begin{Details}\relax
Contrasts are usually used to test if certain means are
significantly different; it can be easier to use \code{se.contrast}
than compute directly with the coefficients.

In multistratum models, the contrasts can appear in more than one
stratum; the contrast and standard error are computed in the lowest
stratum and adjusted for efficiencies and comparisons between strata.\end{Details}
\begin{Value}
A vector giving the standard errors for each contrast.\end{Value}
\begin{Author}\relax
B.D. Ripley\end{Author}
\begin{Examples}
\begin{ExampleCode}
## From Venables and Ripley (1997) p.210.
N <- c(0,1,0,1,1,1,0,0,0,1,1,0,1,1,0,0,1,0,1,0,1,1,0,0)
P <- c(1,1,0,0,0,1,0,1,1,1,0,0,0,1,0,1,1,0,0,1,0,1,1,0)
K <- c(1,0,0,1,0,1,1,0,0,1,0,1,0,1,1,0,0,0,1,1,1,0,1,0)
yield <- c(49.5,62.8,46.8,57.0,59.8,58.5,55.5,56.0,62.8,55.8,69.5,
55.0, 62.0,48.8,45.5,44.2,52.0,51.5,49.8,48.8,57.2,59.0,53.2,56.0)

npk <- data.frame(block=gl(6,4), N=factor(N), P=factor(P),
                  K=factor(K), yield=yield)
options(contrasts=c("contr.treatment", "contr.poly"))
npk.aov1 <- aov(yield ~ block + N + K, npk)
se.contrast(npk.aov1, list(N=="0", N=="1"), data=npk)
\end{ExampleCode}
\end{Examples}

