Руководство по PHP
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# mysqli_insert_id

(PHP 5)

mysqli_insert_id

(no version information, might be only in CVS)

mysqli->insert_id -- Returns the auto generated id used in the last query

## Description

Procedural style:

mixed mysqli_insert_id ( mysqli link )

Object oriented style (property):

class mysqli {
mixed insert_id
}

The mysqli_insert_id() function returns the ID generated by a query on a table with a column having the AUTO_INCREMENT attribute. If the last query wasn't an INSERT or UPDATE statement or if the modified table does not have a column with the AUTO_INCREMENT attribute, this function will return zero.

> Замечание: Performing an INSERT or UPDATE statement using the LAST_INSERT_ID() function will also modify the value returned by the mysqli_insert_id() function.

## Возвращаемые значения

The value of the AUTO_INCREMENT field that was updated by the previous query. Returns zero if there was no previous query on the connection or if the query did not update an AUTO_INCREMENT value.

> Замечание: If the number is greater than maximal int value, mysqli_insert_id() will return a string.

## Примеры

Пример 1. Object oriented style
`<?php $mysqli = new mysqli("localhost", "my_user", "my_password", "world"); /* check connection */ if (mysqli_connect_errno()) { printf("Connect failed: %s\n", mysqli_connect_error()); exit(); } $mysqli->query("CREATE TABLE myCity LIKE City"); $query = "INSERT INTO myCity VALUES (NULL, 'Stuttgart', 'DEU', 'Stuttgart', 617000)"; $mysqli->query($query); printf ("New Record has id %d.\n", $mysqli->insert_id); /* drop table */ $mysqli->query("DROP TABLE myCity"); /* close connection */ $mysqli->close(); ?>`

Пример 2. Procedural style
`<?php $link = mysqli_connect("localhost", "my_user", "my_password", "world"); /* check connection */ if (mysqli_connect_errno()) { printf("Connect failed: %s\n", mysqli_connect_error()); exit(); } mysqli_query($link, "CREATE TABLE myCity LIKE City"); $query = "INSERT INTO myCity VALUES (NULL, 'Stuttgart', 'DEU', 'Stuttgart', 617000)"; mysqli_query($link, $query); printf ("New Record has id %d.\n", mysqli_insert_id($link)); /* drop table */ mysqli_query($link, "DROP TABLE myCity"); /* close connection */ mysqli_close($link); ?>`

Результат выполнения данного примера:

    New Record has id 1.

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mysqli_init | Уровень выше | mysqli_kill