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Lesson: Interfaces
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Answers to Questions and Exercises:

### Questions

> 1. Question: This lesson mentions three ways to traverse a `List`. Describe them, and note the limitations of each.

>    Answer:
>    - Use the enhanced `for` statement:

>      >     List<Thing> list;
>      >     ...
>      >     for (Thing thing : list) {
>      >         ...
>      >     }

>      Limitations: cannot be used to add, remove, or modify elements.
>    - Use the traditional `for` statement together with an `Iterator`:

>      >     List<Thing> list;
>      >     ...
>      >     for (Iterator<Thing> it = list.iterator(); it.hasNext(); ) {
>      >         Thing thing = it.next();
>      >         ...
>      >     }

>      Limitations: cannot be used to modify elements.
>    - Use the traditional `for` statement together with an `ListIterator`:

>      >     List<Thing> list;
>      >     ...
>      >     for (ListIterator<Thing> it = list.iterator(); it.hasNext(); ) {
>      >         Thing thing = it.next();
>      >         ...
>      >     }

>      Limitations: none.
> 2. Question: Consider the four core interfaces, `Set`, `List`, `Queue`, and `Map`. For each of the following four assignments, specify which of the four core interfaces is best-suited, and explain how to use it to implement the assignment.

>    Answer:
>    - Whimsical Toys Inc (WTI) needs to record the names of all its employees. Every month, an employee will be chosen at random from these records to receive a free toy.
>      Use a `List`. Choose a random employee by picking a number between `0` and `size()-1`.
>    - WTI has decided that each new product will be named after an employee — but only first names will be used, and each name will be used only once. Prepare a list of unique first names.
>      Use a `Set`. Collections that implement this interface don't allow the same element to be entered more than once.
>    - WTI decides that it only wants to use the most popular names for its toys. Count up the number of employees who have each first name.
>      Use a `Map`, where the keys are first names, and each value is a count of the number of employees with that first name.
>    - WTI acquires season tickets for the local lacrosse team, to be shared by employees. Create a waiting list for this popular sport.
>      Use a `Queue`. Invoke `add()` to add employees to the waiting list, and `remove()` to remove them.

> 3. Question: The following program is supposed to print the string "Blue". Instead, it throws an error. Why?

>    >     import java.util.*;

>    >     public class SortMe {
>    >         public static void main(String args[]) {
>    >             SortedSet<StringBuffer> s = new TreeSet<StringBuffer>();
>    >             s.add(new StringBuffer("Red"));
>    >             s.add(new StringBuffer("White"));
>    >             s.add(new StringBuffer("Blue"));
>    >             System.out.println(s.first());
>    >         }
>    >     }

>    Answer: `TreeSort` elements must be instances of a class that implements `Comparable`. `StringBuffer` does not.

### Exercises

> 1. Exercise: Write a program that prints its arguments in random order. Do not make a copy of the argument array.

>    Answer:

>    >     import java.util.*;

>    >     public class Ran {
>    >         public static void main(String[] args) {
>    >             List<String> argList = Arrays.asList(args);
>    >             Collections.shuffle(argList);
>    >             for (String arg: argList) {
>    >                 System.out.format("%s ", arg);
>    >             }
>    >             System.out.println();
>    >         }
>    >     }

> 2. Exercise: Take the `FindDups example` and modify it to use a `SortedSet` instead of a `Set`. Specify a `Comparator` so that case is ignored when sorting and identifying set elements.

>    Answer:

>    >     import java.util.*;

>    >     public class FindDups {

>    >         public static void main(String[] args) {
>    >             Comparator<String> comparator = new Comparator<String>() {
>    >                 public int compare (String s1, String s2) {
>    >                     return s1.compareToIgnoreCase(s2);
>    >                 }
>    >             };

>    >             SortedSet<String> s = new TreeSet<String>(comparator);
>    >             for (String a : args)
>    >                 if (!s.add(a))
>    >                     System.out.println("Duplicate detected: " + a);

>    >             System.out.println(s.size() + " distinct words: " + s);
>    >         }
>    >     }

> 3. Exercise: Write a method that takes a `List<String>` and applies `String.trim` to each element. To do this, you'll need to pick one of the three iteration idioms that you described in Question 1. Two of these will not give the result you want, so be sure to write a program that demonstrates that the method actually works!

>    Answer: The enhanced `for` statement does not allow you to modify the `List`. Using an `Iterator` allows you to add and delete elements, but not replace existing element. That leaves `ListIterator`:

>    >     import java.util.*;

>    >     public class ListTrim {
>    >         static void listTrim(List<String> strings) {
>    >             for (ListIterator<String> lit = strings.listIterator();
>    >                     lit.hasNext(); ) {
>    >                 lit.set(lit.next().trim());
>    >             }
>    >         }

>    >         public static void main(String[] args) {
>    >             List<String> l = Arrays.asList(" red ", " white ", " blue ");
>    >             listTrim(l);
>    >             for (String s : l) {
>    >                 System.out.format("\"%s\"%n", s);
>    >             }
>    >         }
>    >     }

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